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Q.

According to Crystal field theory, the complex with a CFSE of -2.4 $Δ_{o}$ is (assuming pairing energy is ignored)

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a

${[{FeF}_{6}]}^{- 3}$

b

${[Fe {(CN)}_{6}]}^{- 3}$

c

${[{FeF}_{6}]}^{- 4}$

d

${[Fe {(CN)}_{6}]}^{- 4}$

answer is D.

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Detailed Solution

$F^{-}$ is a weak field ligand; ${CN}^{-}$ is a strong field ligand;

	$M^{+ n}$	field strength	configuration	CFSE
1)	${Fe}^{+ 3}$	$Δ_{o} < P$	$3 d^{5} (t_{2 g}^{3} e_{g}^{2})$	$Zero$
2)	${Fe}^{+ 3}$	$Δ_{o} > P$	$3 d^{5} (t_{2 g}^{5})$	$- 2 Δ_{o}$
3)	${Fe}^{+ 2}$	$Δ_{o} < P$	$3 d^{6} (t_{2 g}^{4} e_{g}^{2})$	$- 0 .4 Δ_{o}$
4)	${Fe}^{+ 2}$	$Δ_{o} > P$	$3 d^{6} (t_{2 g}^{6})$	$- 2 .4 Δ_{o}$

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