According to Joule's law of heating, the heat produced $H = I^{2} Rt$ where I is current, R is resistance and t is time. If the error in the measurement of I, R and t are 3%, 4% and 6% respectively then the error in the measurement of H is:

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$\pm 19 %$

$\pm 17 %$

$\pm 16 %$

$\pm 25 %$

answer is B.

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Detailed Solution

$\begin{array}{l} H = I^{2} Rt \\ ∴ \frac{ΔH}{H} \times 100 = (\frac{2 ΔI}{I} + \frac{ΔR}{R} + \frac{Δt}{t}) \\ \times 100 \\ = (2 \times 3 + 4 + 6) % = 16 % \end{array}$

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