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Q.

According to law of mass action, for CaCO₃ $⇌$ CaO + CO₂ (R_f = Rate of forward and R_b = Rate of backward reactions)

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a

R_{b} = K_{b} [{CO}_{2}]

b

R_{b} = K_{b} {[{CaCO}_{3}]}^{2}

c

R_{f} = K_{f} [CaO]

d

\frac{R_{f}}{R_{b}} = [{CO}_{2}]

answer is A.

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Detailed Solution

$large CaC{O_3}(s), rightleftharpoons ,CaO(s), + ,C{O_2}(g)$

At equilibrium applying law of mass action to backward reaction.

r_b = k_b [CO₂]

Note: CaCO, CaO are solids. Their concentration changes are negligible and law of mass aciton cannot be applied.

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