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Q.

According to law of mass action, for  CaCO3⇌CaO + CO2  (Rf = Rate of forward and Rb = Rate of backward reactions)

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a

RfRb=CO2

b

Rb=KbCO2

c

Rb=KbCaCO32

d

Rf=KfCaO

answer is A.

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Detailed Solution

\large CaC{O_3}(s)\, \rightleftharpoons \,CaO(s)\, + \,C{O_2}(g)

At equilibrium applying law of mass action to backward reaction.

rb = kb [CO2]

Note: CaCO, CaO are solids. Their concentration changes are negligible  and law of mass aciton cannot be applied.

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