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According to Molecular orbital theoty, correct stability order in the following species is

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$O_{2}^{+} > O_{2} > O_{2}^{-} > O_{2}^{- 2}$

$O_{2}^{-} > O_{2} > O_{2}^{+} > O_{2}^{- 2}$

$O_{2}^{- 2} > O_{2}^{-} > O_{2} > O_{2}^{+}$

$O_{2}^{+} > O_{2}^{- 2} > O_{2}^{-} > O_{2}$

answer is A.

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Detailed Solution

$\begin{array}{l} O_{2}^{+} - \frac{10 - 5}{2} = 2 .5; \\ O_{2} - \frac{10 - 6}{2} = 2; \\ O_{2}^{-} = \frac{10 - 7}{2} = 1.5; \\ O_{2}^{- 2} - \frac{10 - 8}{2} = 1; \end{array}$

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