According to Mulliken, which of the following relation is correct?

When E.N. stands for electronegativity, E.A. stands for electron affinity and I.P. stands for Ionization potential.
It is observed that for an element, E.A. and E.N. and I.P. usually vary in the same direction. Hence, when E.A. and E.N. and I.P. also increases E.N. has the mean valued of I.P. and E.A. 

$\mathrm{E}\cdot \mathrm{N}.=\frac{\mathrm{I}\cdot \mathrm{P}\cdot +\mathrm{E}\cdot \mathrm{A}.}{2}$

$\therefore 2\mathrm{E}\cdot \mathrm{N}.=\mathrm{I}\cdot \mathrm{P}.+\mathrm{E}\cdot \mathrm{N}\cdot$ or $2\mathrm{E}\cdot \mathrm{N}.-\mathrm{I}\cdot \mathrm{P}.-\mathrm{E}\cdot \mathrm{A}.=0$

Hence, the option B is correct