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Q.

According to Newton’s second law of motion, resultant force on a particle is in the direction of acceleration of the particle. Two force $F_{1}$ and $F_{2}$ are acting on a particle as shown in the figure. The acceleration of the particle is along X-axis. Find the value of $F_{1}$ (in newton)

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answer is 6.

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Detailed Solution

Since, acceleration of particle is along X-axis. So, net force will be along X-axis

$Hence, \sum F_{Y} = 0$

$∴ F_{2} \sin 37^{\circ} - F_{1} \sin 30^{\circ} = 0 or \frac{3}{5} F_{2} = \frac{F_{1}}{2}$

$∴ F_{1} = \frac{6}{5} \times 5 = 6 N$ .

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According to Newton’s second law of motion, resultant force on a particle is in the direction of acceleration of the particle. Two force F1 and F2 are acting on a particle as shown in the figure. The acceleration of the particle is along X-axis. Find the value of F1 (in newton)