According to the Bohr theory of hydrogen atom, the angular momentum of an electron in any orbit of hydrogen atom is

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Directly proportional to the square root of the radius of the orbit.

Directly proportional to the radius of the orbit.

Directly proportional to the square of the radius of the orbit.

Inversely proportional to the radius of the orbit.

answer is A.

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Detailed Solution

$mvr = \frac{nh}{2 π}$

$i . e r \infty n^{2}$

Angular momentum = mvr

Velocity of $e^{-} = \frac{K}{n}$

Radius of orbit $= {cn}^{2}$

$\sqrt{\frac{r}{c}}$

Angular momentum= $m \times \frac{K}{n} \times r = \frac{cmk}{\sqrt{n}} r = a \sqrt{r} = a is consatant$ $\Rightarrow Angular momentum \infty \sqrt{r}$

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