According to the equation,

${\mathrm{N}}_2{\mathrm{O}}_3\left(g\right)+6{\mathrm{H}}_2\left(\mathrm{g}\right)⟶2{\mathrm{NH}}_3\left(g\right)+3{\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right)$

how many moles of ${\mathrm{NH}}_3\left(\mathrm{g}\right)$ could be formed from the reaction of 0.22 mol of ${\mathrm{N}}_2{\mathrm{O}}_3\left(\mathrm{g}\right)$ with 0.87 mol of ${\mathrm{H}}_2\left(\mathrm{g}\right)$?