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Q.

Acetamide reacts with NaOBr in alkaline medium to form :

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a

${CH}_{3} {NH}_{2}$

b

${CH}_{3} CN$

c

${NH}_{3}$

d

$C_{2} H_{5} {NH}_{2}$

answer is B.

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Detailed Solution

This is Hofmann degradation, where loss of one carbon occurs due to formation of unstable carbamic aicd.

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