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Q.

Acetamide reacts with ${Br}_{2} / NaOH$ to give

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a

${CH}_{3} {CH}_{2} {NH}_{2}$

b

${CH}_{3} COOH$

c

${CH}_{3} {NH}_{2}$

d

${CH}_{3} Br$

answer is B.

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Detailed Solution

${RCONH}_{2} \overset{{OBr}^{-}}{⟶} {RNH}_{2} + {CO}_{3}^{2 -}$ .

The reaction occurs through intermediate formation of alkyl isocyanate which on hydrolysis gives methylamine and sodium carbonate.

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