Acetone on distillation with bleaching powder and water gives chloroform and X. Ethyl alcohol on distillation with bleaching powder and water gives ${CHCI}_{3}$ , and Y. X and Y together on distillation gives

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${CH}_{3} {COC}_{2} H_{5}$

${CH}_{2} = CHOH$

${CH}_{3} CHO$

${CH}_{3} {COCH}_{3}$

answer is A.

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Detailed Solution

Bleaching powder Calcium hydroxide (slaked lime) and chlorine are provided for the reaction by ${CaOCl}_{2}$ .
${CaOCl}_{2} + H_{2} O \to Ca {(OH)}_{2} + {Cl}_{2}$
The chlorine generated in this manner serves as both a chlorinating and a moderate oxidising agent. Trichloroacetone is formed when acetone is chlorinated. ${CH}_{3} {COCH}_{3} + 3 {Cl}_{2} \to {CCl}_{3} {COCH}_{3} + 3 HCl$ Chloroform is formed during trichloroacetate hydrolysis. $2 {CCl}_{3} {COCH}_{3} + Ca {(OH)}_{2} \to 2 {CHCl}_{3} + {({CH}_{3} COO)}_{2} Ca$ (X) Bleaching powder combined with ethanol or acetone can be used to create chloroform in a laboratory setting. Bleaching powder serves as an oxidising, chlorinating, and hydrolyzing agent in this reaction. $2 {CCl}_{3} CHO + Ca {(OH)}_{2} \to 2 {CHCl}_{3} + {(HCOO)}_{2} Ca$ (Y) Therefore, X and Y together on distillation gives acetaldehyde (CH₃CHO). Hence, the correct option is option (A) ${CH}_{3} CHO$ .