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Acetone on reacting with ${CH}_{3} MgBr$ followed by hydrolysis produces

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sec-butyl alcohol

isobutyl alcohol

n-butyl alcohol

tert-butyl alcohol

answer is D.

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Detailed Solution

Step 1: Reaction of acetone with CH₃MgBr (a Grignard reagent).

Acetone = CH₃–CO–CH₃.

CH₃MgBr attacks the carbonyl carbon, forming an alkoxide intermediate:

CH₃–C(OMgBr)–CH₃ with an extra CH₃ group attached to the carbonyl carbon.

Product before hydrolysis: (CH₃)₃C–OMgBr.

Step 2: Hydrolysis.

On adding water, the OMgBr group converts into –OH.

Final product = (CH₃)₃C–OH.

That compound is tert-butyl alcohol.

Correct answer: d) tert-butyl alcohol.

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