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Q.

Acetylene on acidic hydration gives ‘X’; Ethene on acidic hydration gives ‘Y’. ‘Y’ and ‘X’ are respectively

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a

1^o alcohol ; Aldehyde

b

Aldehyde ; Ketone

c

1^o alcohol ; Carboxylic acid

d

Vinyl alcohol ; Aldehyde

answer is A.

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Detailed Solution

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$\underset{Acetylene}{CH \equiv CH} \to_{{HgSO}_{4}}^{H_{2} O, dil . H_{2} {SO}_{4}} [{CH}_{2} = CH - OH]$

$\overset{tautomerism}{⇌} \underset{X}{{CH}_{3} - CHO}$

$\underset{Ethene}{{CH}_{2} = {CH}_{2}} \overset{H_{3} O^{+}}{\to} \underset{(Y)}{{CH}_{3} - {CH}_{2} - OH}$

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