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Acetylene reacts with hydrogen in presence of Palladium and Barium sulphate in quinoline to give ‘X' 1,1,2,2 - tetrabromo ethane on heating with excess of ethanolic zinc dust gives ‘Y’. ‘X’ and ‘Y’ are respectively

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$C_{6} H_{6}, C_{2} H_{4}$

$C_{2} H_{4}, C_{2} H_{2}$

$C_{2} H_{4}, C_{2} H_{6}$

$C_{2} H_{6}, C_{2} H_{4}$

answer is B.

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Detailed Solution

$C_{2} H_{2} \to_{Lindlar' scatalyst}^{H_{2}} {CH}_{2} = {CH}_{2}$
${CHBr}_{2} - {CHBr}_{2} \to_{∆}^{Zn / C_{2} H_{5} OH} CH \equiv CH$

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