Acidic K2S2O8 can oxidize MnO2 to MnO4- and acidic K2S2O8 and acidic MnO2 oxidize I–, Br–, Cl– to I2, Br2 and Cl2 respectively. From this information, the sequence that represents the correct order of increasing oxidation ability as

acidic K 2 S 2 O 8 > acidic MnO 2 > Cl 2

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Acidic K₂S₂O₈ can oxidize MnO₂ to ${MnO}_{4}^{-}$ and acidic K₂S₂O₈ and acidic MnO₂oxidize I^–, Br^–, Cl^– to I₂, Br₂ and Cl₂ respectively. From this information, the sequence that represents the correct order of increasing oxidation ability as

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I₂ > K₂S₂O₈ > Br₂

Cl₂ > K₂S₂O₈ > Br₂

K₂S₂O₈ > I₂ > Br₂

acidic K₂S₂O₈ > acidic MnO₂ > Cl₂

answer is B.

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Acidic K₂S₂O₈ can oxidize MnO₂ to ${MnO}_{4}^{-}$

$K_{2} {\overset{+ 6}{S}}_{2} O_{8} + 2 \overset{+ 4}{Mn} O_{2} \to 2 K \overset{+ 7}{Mn} O_{4} + 2 \overset{+ 4}{S} O_{2}$

acidic K₂S₂O₈ > acidic MnO₂ > Cl₂

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