Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the manganese product formed from the above reaction is______ B.M. (Nearest Integer)

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answer is 6.

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Detailed Solution

$2 {KMnO}_{4} + 5 H_{2} C_{2} O_{4} + 3 H_{2} {SO}_{4} \to K_{2} {SO}_{4} + 2 \overset{+ 2}{Mn} {SO}_{4} + 10 {CO}_{2} + 8 H_{2} O$ ${Mn}^{2 +}$ has 5 unpaired electrons therefore the magnetic moment is $\sqrt{n (n + 2)}$

$\sqrt{5 (5 + 2)}$

$\sqrt{35} BM$

= 6

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