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Q.

Acidified potassium permanganate solution oxidises oxalic acid. The spin-only magnetic moment of the manganese product formed from the above reaction is______ B.M. (Nearest Integer)

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answer is 6.

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Detailed Solution

$2 K M n O_{4} + 5 H_{2} C_{2} O_{4} + 3 H_{2} S O_{4} \to K_{2} S O_{4} + 2 \overset{+ 2}{M n} S O_{4} + 10 C O_{2} + 8 H_{2} O$

$M n^{2 +}$ has 5 unpaired electrons. Therefore, the magnetic moment is $\sqrt{n (n + 2)}$

$\sqrt{5 (5 + 2)} = \sqrt{35} = 5.91 \approx 6 B M$

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