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Acidified solution of chromic acid on treatment with H₂O₂, gives blue colour which is due to

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${CrO}_{3} + H_{2} O + O_{2}$

${Cr}_{2} O_{3} + H_{2} O + O_{2}$

${CrO}_{5} + H_{2} O$

$H_{2} Cr 2 O_{7} + H_{2} O + O_{2}$

answer is C.

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Detailed Solution

$K_{2} {Cr}_{2} O_{7} + H_{2} {SO}_{4} + 4 H_{2} O_{2} ⟶ 2 {CrO}_{5} + K_{2} {SO}_{4} + 5 H_{2} O$

Chromic peroxide

The blue colour due to chromic peroxide fades away gradually due to decomposition of

${CrO}_{5} to {Cr}^{3 +}$ ions and oxygen.

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