A=cos 200-sin 200, B = cos 1000+ sin 1000, C=cos5π6+sin2π3 then the ascending order is

A=cos200-sin200>0B=cos1000+sin1000 =cos100-sin100>0C=cos5π6+sin2π3=-32+32=0ascending order C, A, B

A=cos 200-sin 200, B = cos 1000+ sin 1000, C=cos5π6+sin2π3 then the ascending order is

A=cos200-sin200>0B=cos1000+sin1000 =cos100-sin100>0C=cos5π6+sin2π3=-32+32=0ascending order C, A, B

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$A = \cos 20^{0} - \sin 20^{0}, B = \cos 100^{0} + \sin 100^{0},$ $C = \cos \frac{5 π}{6} + \sin \frac{2 π}{3}$ then the ascending order is

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A, B, C

B, C, A

C, A, B

C, B, A

answer is A.

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$\begin{array}{rcl} A & = & \cos 20^{0} - \sin 20^{0} > 0 \\ B & = & \cos 100^{0} + \sin 100^{0} \\ = & \cos 10^{0} - \sin 10^{0} > 0 \\ C & = & \cos \frac{5 π}{6} + \sin \frac{2 π}{3} = \frac{- \sqrt{3}}{2} + \frac{\sqrt{3}}{2} = 0 \end{array}$

ascending order C, A, B

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A=cos 200-sin 200, B = cos 1000+ sin 1000, C=cos5π6+sin2π3 then the ascending order is

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$A = \cos 20^{0} - \sin 20^{0}, B = \cos 100^{0} + \sin 100^{0},$ $C = \cos \frac{5 π}{6} + \sin \frac{2 π}{3}$ then the ascending order is