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Q.

acotA+bcotB+ccotC is equal to

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a

r-R

b

r+R

c

2(r+R)

d

2(r-R)

answer is C.

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Detailed Solution

acotA+bcotB+ccotC=2R(sinAcotA+sinBcotB+sinCcotC]=2R(cosA+cosB+cosC)=2R1+4sin12Asin12Bsin12C=2R1+rR=2(R+r).

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