Across a long conductor 2A current is flowing. At 10cm from it another 5cm long conductor carries 3A. The values of B at short conductor and force on it, in the multiple of 10^–6 are

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6N, 6T

6N, 0.4T

4T, 0.6N

4T, 6N

answer is B.

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Detailed Solution

$B = \frac{μ_{0} i_{1}}{2 πr} = \frac{4 π \times 10^{- 7} \times 2}{2 π \times 10 \times 10^{- 2}} = 4 \times 10^{- 6} T$
Force on short conductor
$F = {Bi}_{2} l = 4 \times 10^{- 6} \times 3 \times 5 \times 10^{- 2} = 0.6 \times 10^{- 6} N$

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