Action of caustic soda and chlorine on ethyl alcohol gives

When chlorine reacts with ethyl alcohol (in the presence of NaOH), chloroform forms as a final product.

$$\begin{gathered} {\mathrm{Cl}}_2+{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH}\stackrel{\mathrm{oxidation}}{\to }{\mathrm{CH}}_3\mathrm{CHO}+2\mathrm{HCl} \\ {\mathrm{CCl}}_3\mathrm{CHO}+\mathrm{NaOH}\stackrel{\mathrm{hydrolysis}}{\to }{\mathrm{CHCl}}_3+\mathrm{HCOONa} \end{gathered}$$