Activation energy of an uncatalysed reaction at 1000 K is 5 Kcal. In presence of catalyst the activation energy of same reaction at same temperature will be (Ratio of rate constants of catalyzed reaction to uncatalysed reaction is 10:1)

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

2303 cal

931 cal

394 cal

4606 cal

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$K_{catalyst} = {Ae}^{- \frac{{E_{a}}_{1}}{RT}}$

$K_{un catalyst} = {Ae}^{- \frac{{E_{a}}_{2}}{RT}}$

$\frac{K_{C}}{K_{UC}} = e^{\frac{E_{a_{(2)}} - E_{a_{(1)}}}{R T}}$

$\log \frac{K_{c a t a l y s t}}{K_{u n c a t a l y s t}} = \frac{E_{a_{(2)}} - E_{a_{(1)}}}{2.303 R T}$

$E_{a_{(2)}} - E_{a_{(1)}} = 4606 cal$

Activation energy of catalysed reaction E_a1 = 5000 - 4606 = 394 cal

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE