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Q.

Actual shape of the molecule ${BrF}_{5}$ is similar to the molecule:

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a

${PCl}_{5}$

b

none of these

c

${PCl}_{4}^{+}$

d

${XeF}_{4}$

answer is D.

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Detailed Solution

${BrF}_{5}$ is square pyramidal.

The shape of XeF₄ is square planar.

PCl ₅ shape is trigonal bipyramidal.

The shapes of PCl₄+,is tetrahedral,

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