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Q.

Addition of ${Br}_{2}$ takes place readily with

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a

${CH}_{2} = {CH}_{2}$

b

${CH}_{3} - \underset{{CH}_{3}}{\underset{|}{C = CH - {CH}_{3}}}$

c

${CH}_{3} - CH = {CH}_{2}$

d

${CH}_{3} - CH = CH - {CH}_{3}$

answer is D.

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Detailed Solution

The double bond breaks, and a bromine atom becomes attached to each carbon. The bromine loses its original red-brown color to give a colorless liquid.
Addition of ${Br}_{2}$ takes place readily with ${CH}_{3} - \underset{{CH}_{3}}{\underset{|}{C = CH - {CH}_{3}}}$ because it has more number of alpha hydrogen.

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