Additive inverse of the rational expression x-1x will be:

Concept: The fact that the additive identity, or 0 is equal to the sum of the number and its additive inverse.Assume that A is the x-1x expression's additive inverse. Utilise This, demonstrate that A+x-1x=0. Use the fact that an equation's solution set remains the same when equal amounts are added to or subtracted from both sides of the equation. Consequently, add 1x to both sides of the equation and deduct x from both sides. Consequently, calculate A's value in terms of x. Check your response.Let A be the additive inverse of the term x-1xwe haveA+x-1x=0 We know that the addition of equal terms on both sides of the equation does not change the solution set of the equation.A+x=1x we getA=1x-x Rewriting, we get the ans is A=-x+1xHence, the correct option is (2) .

Additive inverse of the rational expression x-1x will be:

Concept: The fact that the additive identity, or 0 is equal to the sum of the number and its additive inverse.Assume that A is the x-1x expression's additive inverse. Utilise This, demonstrate that A+x-1x=0. Use the fact that an equation's solution set remains the same when equal amounts are added to or subtracted from both sides of the equation. Consequently, add 1x to both sides of the equation and deduct x from both sides. Consequently, calculate A's value in terms of x. Check your response.Let A be the additive inverse of the term x-1xwe haveA+x-1x=0 We know that the addition of equal terms on both sides of the equation does not change the solution set of the equation.A+x=1x we getA=1x-x Rewriting, we get the ans is A=-x+1xHence, the correct option is (2) .

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Additive inverse of the rational expression $x - \frac{1}{x}$ will be:

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x + \frac{1}{x}

- x + \frac{1}{x}

x^{2} - \frac{1}{x}

\frac{- 1}{x} + x

answer is B.

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Detailed Solution

Concept: The fact that the additive identity, or 0 is equal to the sum of the number and its additive inverse.
Assume that A is the

x - \frac{1}{x}

expression's additive inverse. Utilise This, demonstrate that

A + x - \frac{1}{x} = 0

. Use the fact that an equation's solution set remains the same when equal amounts are added to or subtracted from both sides of the equation. Consequently, add

\frac{1}{x}

to both sides of the equation and deduct x from both sides. Consequently, calculate A's value in terms of x. Check your response.
Let A be the additive inverse of the term