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After adding a solute freezing point of solution decreases to $- 0.186$ .
Calculate $Δ T_{b} if K_{f} = 1.86 and K_{b} = 0.521$

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0.0521

0.521

0.0186

1.86

answer is B.

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Detailed Solution

$Δ T_{f} = K_{f} \times m \Rightarrow 0.186 = 1.86 \times m$

So $m = 0.1,$ Put the value of $m$ in $Δ T_{b} = K_{b} \times m$

$Δ T_{b} = 0.521 \times (0.1) = 0.0521$

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