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Q.

Ag+3Bg 4Cg . Initial concentration of A is equal to that of B. The equilibrium concentration of A and C are equal. KC is equal to :

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a

0.08

b

8

c

1/8

d

80

answer is B.

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Detailed Solution

A  +  3B   4C

Initial :   1      1           0
Equilib  : 1-x  1-3x     4x

[A] = [C]
1 – x = 4x   x = 0.2
[A] = 1-0.2 = 0.8
[B] = 1- 3x : 1 – 0.6 = 0.4, [C] = 4x = 0.8

KC=C4AB3= 0.840.80.43=8

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