Ag⁺ ion concentration in saturated solution of ${Ag}_{3} {PO}_{4} (K_{s p} = 2.7 \times 10^{- 19})$ :

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$10^{- 4} M$

$3 \times 10^{- 5} M$

$\begin{aligned} 2.7 \times 10^{- 4} M \end{aligned}$

$\begin{aligned} 10^{- 5} M \end{aligned}$

answer is C.

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Detailed Solution

Ag⁺ ion concentration in saturated solution,

$\begin{array}{l} K_{S P} = {[{Ag}^{+}]}^{3} [{PO}_{4}] \\ K_{S P} = (3 s)^{3} \times S \\ {Ksp}^{} = 27 S^{4} \end{array}$

$3 S \Rightarrow 3 x {(\frac{k_{s} p}{27})}^{1 / 4}$

$[{Ag}^{+}] = 3 \times \sqrt[4]{\frac{2.7 \times 10^{- 19}}{27}}$

$[{Ag}^{+}] =$ $3 \times 10^{- 5} M$

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