Q.

A(g)+2B(s)2C(g)

Initially 2 mole A(g), 4 mole of B(s) and 1 mole of an inert gas are present in a closed container. After equilibrium has established, total pressure of container becomes 9 atm. If A(g) is 50% consumed at equilibrium, then, calculate KP for the above reaction:

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a

12 atm

b

9 atm

c

365atm

d

23atm

answer is A.

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Detailed Solution

We have the following reaction;

               A(g)+2B(s)2C(g) t=0             2        4           t=teq         1            2             2

KP=24×9214×9 =9

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