Ag2S+NaCN→AA+Zn→BB is a metal. Hence A and B:

Ag2S+4NaCN→2Na[Ag(CN)4](A)+Na2S2Na[Ag(CN)4](a)→ZnAg↓+ (B)Na2[Zn(CN)4](Impure)

Ag2S+NaCN→AA+Zn→BB is a metal. Hence A and B:

Ag2S+4NaCN→2Na[Ag(CN)4](A)+Na2S2Na[Ag(CN)4](a)→ZnAg↓+ (B)Na2[Zn(CN)4](Impure)

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$\begin{array}{l} {Ag}_{2} S + NaCN \to A \\ A + Zn \to B \end{array}$
B is a metal. Hence A and B:

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${Na}_{2} [Zn {(CN)}_{4}], Zn$

$Na [Ag {(CN)}_{4}], Ag$

$Na [Ag {(CN)}_{2}], Ag$

${Na}_{3} [Ag {(CN)}_{4}], Ag$

answer is B.

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Detailed Solution

$\begin{array}{l} {Ag}_{2} S + 4 NaCN \to \underset{(A)}{2 Na [Ag {(CN)}_{4}]} + {Na}_{2} S \\ \underset{(a)}{2 Na [Ag {(CN)}_{4}]} \overset{Zn}{\to} \underset{(B)}{Ag ↓ +} \underset{(Impure)}{{Na}_{2} [Zn {(CN)}_{4}]} \end{array}$

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