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${Ag}_{2} S + NaCN ⟶ (A) (A) + Zn ⟶ (B)$
Determine (A) and (B).

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${Na}_{2} [Zn (CN)_{4}], Zn$

${Na}_{3} [Ag (CN)_{4}], Ag$

${Na}_{2} [Ag (CN)_{4}], Ag$

$Na [Ag (CN)_{2}], Ag$

answer is B.

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Detailed Solution

${Ag}_{2} S + 4 NaCN \to \underset{A}{2 Na [Ag {(CN)}_{2}]} + {Na}_{2} S 2 Na [Ag (CN)_{2}] + Zn \to {Na}_{2} [Zn {(CN)}_{4}] + \underset{B}{2 Ag}$

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