$\mathrm{Ag}\left|\mathrm{AgCl}\right|{\mathrm{Cl}}^{-}\left({\mathrm{C}}_2\right)\parallel {\mathrm{Cl}}^{-}\left({\mathrm{C}}_1\right)\left|\mathrm{AgCl}\right|\mathrm{Ag}$ for this cell $\mathrm{\Delta G}$ is negative if:

Given cell is Concentration cell $Anode : Ag+C{l}_{\left(c_2\right)}^{-}\to AgCl+e^{-}$

$$\begin{gathered} \frac{C:-AgCl+e^{-}\to Ag+C{l}_{\left(c_1\right)}^{-}}{C{l}_{\left(c_2\right)}^{-}\to C{l}_{\left(c_1\right)}^{-}} \\ {E}_{cell}=\frac{-0.059}{1}\log \frac{c_1}{c_2} \\ =\frac{0.059}{1}\log \frac{c_2}{c_1} \end{gathered}$$

If$c_2>c_1,E_{cell}=+ve,\mathrm{\Delta }G=-ve$