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AgCl and Ag₂CrO₄ are two sparingly soluble salts. Their solubility products are equal and each equal to 4 $x$ 10^-18, then which among the following is true

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Solubility of AgCl is more than Ag₂CrO₄

Solubility of Ag₂CrO₄ is more than AgCl

Solubility of Ag₂CrO₄ is equal to AgCl

Solubility of Ag₂CrO₄ is $10 \times 10^{-6}$

answer is B.

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Detailed Solution

: AgCl, Ksp = $s^{2}$ = 4 x $10^{- 18}$

$∴$ S = 2 x $10^{- 9} M$

$A g_{2} C r O_{4},$ Ksp = $4 s^{3} = 4 \times 10^{- 18}$

S = $1 \times 10^{- 6} M$

$∴ S_{A g C l} < S_{A g_{2} C r O_{4}}$

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