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$AgN O_{3} + Cu \to Cu (N O_{3})_{2} + Ag$

Which of the following is the correct balanced equation for the given equation?

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AgN O_{3} + 4 Cu \to Cu (N O_{3})_{2} + Ag

2 AgN O_{3} + Cu \to Cu (N O_{3})_{2} + 2 Ag

AgN O_{3} + 2 Cu \to Cu (N O_{3})_{2} + Ag

3 AgN O_{3} + Cu \to Cu (N O_{3})_{2} + Ag

answer is B.

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Detailed Solution

In the given reaction

N O_{3}

is not balanced. Hence multiply by 2 to

AgN O_{3}

2 AgN O_{3} + Cu \to Cu (N O_{3})_{2} + Ag

Multiply by 2 to Ag on the product side to balance the Ag element,

2 AgN O_{3} + Cu \to Cu (N O_{3})_{2} + 2 Ag

Balancing both the sides with equal moles reactant and product.

$Ag = 1 \times 2$ $= 2$	$Ag = 1 \times 2$ $= 2$
$N = 1 \times 2$ $= 2$	$N = 2$
$O = 3 \times 2$ $= 6$	$O = 6$
$Cu = 1$	$Cu = 1$

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