Q.

∑[(a×i)×j]2=

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a

a2

b

2a2

c

3a2

d

4a2

answer is A.

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Detailed Solution

∑a·j i-02=(a·j)2+(a·k)2+(a·i)2

Let a=xi+yj+zk

         =y2+z2+x2=|a|2

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