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Air contains 20% by volume of oxygen. The volume of air required for the complete combustion of 1L of methane under the same conditions is

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10L

0.4L

answer is C.

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Detailed Solution

Volume of O₂ required = 2liters

Volume present of O₂ in air = 20%

Air	O₂
100 ml	20 lit
?	2 l

Volume of air required = $\frac{2}{20} \times 100$ = 10

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