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Air contains 20% $O_{2}$ by volume. How much volume of air will be required for combustion of 100 cc of acetylene?

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500 cc

1064 cc

212.8 cc

1250 cc

answer is D.

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Detailed Solution

$2 C_{2} H_{2} + 5 O_{2} ⟶ 4 {CO}_{2} + 2 H_{2} O$

$\begin{matrix} 2 cc & 5 cc \\ 100 cc & 250 cc \end{matrix}$

$Hence, air will be needed = \frac{100}{20} \times 250 = 1250 cc .$

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