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Q.

Air is pumped into an automobile tube upto a pressure of 200 kPa in the morning when the air temperature is22∘C. During the day, temperature rises to 42∘C and the tube expands by 2%. The pressure of the air in the tube at this temperature will be approximately

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a

212 kPa

b

206 kPa

c

209 kPa

d

200 KPa

answer is B.

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Detailed Solution

P1V1T1=P2V2T2(As no. of moles remains same)

Given, P1=200Kpa, V1=V,

T1=273+22=295K,

V2=V+0.02V, T2=273+42=315K

⇒ P2=200×315295×1.02≈209Kpa

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