Airplanes A and B are flying with constant velocity in the same vertical plane at angles 300 and 600 with respect to the horizontal respectively as shown in the figure. The speed of A is 1003 ms−1. At time t=0 s, an observer in A finds B at a distance of 500m. This observer sees B moving with a constant velocity perpendicular to the line of motion of A. if at t=t0. A just escapes being hit by B, t0 in seconds is

VBcos300=VA VB=200m/s t=SrelVrel=500VBsin300=5

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Airplanes A and B are flying with constant velocity in the same vertical plane at angles $30^{0}$ and $60^{0}$ with respect to the horizontal respectively as shown in the figure. The speed of A is $100 \sqrt{3} m s^{- 1} .$ At time $t = 0 s,$ an observer in A finds B at a distance of 500m. This observer sees B moving with a constant velocity perpendicular to the line of motion of A. if at $t = t_{0} .$ A just escapes being hit by B, $t_{0}$ in seconds is

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answer is 5.

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$V_{B} \cos 30^{0} = V_{A}$
$V_{B} = 200 m / s$
$t = \frac{S_{r e l}}{V_{r e l}} = \frac{500}{V_{B} \sin 30^{0}} = 5$

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