${AlCl}_{3}$ in water at pH < 7 forms

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tetrahedral $Al {(OH)}_{4}^{-}$

Octahedral $Al {(OH)}_{6}^{3 -}$

Octahedral $Al {(H_{2} O)}_{6}^{3 +}$

Square planar $Al {(OH)}_{4}^{-}$

answer is D.

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Detailed Solution

Hydrolysis with water:
When AlCl₃ is dissolved in water, it undergoes hydrolysis rapidly to produce Al(OH)₃ which is a weak base and HCl which is a strong acid.

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