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Q.

A Li2+ ion is in a higher excited state of quantum number ' n '. This excited ion can make a transition to the first excited state by successively emitting

two photons of energies 10.2 eV and 17.0 eV respectively. The value of 'n' is :

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answer is 6.

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Detailed Solution

Here we have given that;

n→2; Z=3ΔE=10.2+17=27.2eV27.2=13.6×32122−1n2⇒ n=6

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