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Alkaline ${KMnO}_{4}$ solution converts acetylene into

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Acetic acid

Acetaldehyde

Oxalic acid

Glycol

answer is B.

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Detailed Solution

When ethyne or acetylene reacts with cold ${KMnO}_{4}$ , they add 4 OH^- to the triple bond. Oxalic acid is formed when a dilute aqueous solution of potassium permanganate oxidizes it.

$C_{2} H_{2} + 4 [O] \overset{{cold alkaline KMnO}_{4}}{⟶} HOOC - COOH$

Therefore, the correct option (B) Oxalic acid.

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