Alkanes having odd carbons cannot be prepared in
A) Wurtz reaction
B) Frankland reaction
C) Kolbe’s electrolysis
D) Sabatier-senderens reaction

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$A, C & D$

$A, B & D$

$A, B & C$

$B, C & D$

answer is D.

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Detailed Solution

Wurtz reaction: The reaction involves the synthesis of higher alkanes from lower alkanes by reduction with sodium metal.
So the product contains double the number of carbon atoms.
Frankland reaction: Use to synthesize dialkylzinc from alkyl halides.
So the product contains double the number of carbon atoms.
Kolbe’s electrolysis: In this reaction, sodium acetate is electrolyzed to form an acetate ion which decomposed to form methyl radical.
The methyl radical may combine with other methyl radicals can produce ethane.
So the product contains double the number of carbon atoms.
Sabatier-sendersen reaction: Hydrogenation of alkenes produces alkanes. Therefore alkanes with odd carbon atoms can be used.

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