All of the following lists include at least one ionic compound except:

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${NO}_{2}, {NaNO}_{2}, {KNO}_{3}$

${CF}_{4}, {CaF}_{2}, HF$

$NaCl, {MgCl}_{2}, {SCl}_{2}$

$H_{2} S, {SO}_{2}, {SF}_{6}$

answer is D.

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Detailed Solution

All of the following lists include at least one ionic compound except $H_{2} S, {SO}_{2}, {SF}_{6}$ are covalent.

Hydrogen sulfide $H_{2} S$ due to the covalent nature of the link formed by two hydrogens and one sulphur. In order for the hydrogen (H) and sulphur (S) atoms to finish their octet shells and achieve stability, they share one electron, forming a covalent connection.

Sulfur dioxide $({SO}_{2})$ Due to the attempt of two sulphur dioxide atoms with identical electronegativity to link together, sulphur dioxide is a covalent molecule. As a result, the two atoms share electron bonds to create covalent bonds due to the minor variation in electronegativity between them

sulphur hexafluoride $({SF}_{6})$ All of the bonds in ${SF}_{6}$ are covalent since they connect two non-metals. The substance is a covalent compound as well.

Hence, option D is correct.

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