All of the following substances react with water. The pair that gives the same gaseous product is

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Ba and BaO₂

K and KO₂,

Ca and CaH₂,

Na and Na₂O₂

answer is C.

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Detailed Solution

$Ca and {CaH}_{2} both react with H_{2} O to form H_{2} gas, Ca + 2 H_{2} O ⟶ Ca (OH)_{2} + H_{2} {CaH}_{2} + 2 H_{2} O ⟶ Ca (OH)_{2} + 2 H_{2} whereas K gives H_{2} while {KO}_{2} gives O_{2} and H_{2} O_{2} 2 K + 2 H_{2} O ⟶ 2 KOH + H_{2} 2 {KO}_{2} + 2 H_{2} O ⟶ 2 KOH + O_{2} + H_{2} O_{2} Similarly, Na gives H_{2} while {Na}_{2} O_{2} gives H_{2} O_{2} 2 Na + 2 H_{2} O ⟶ 2 NaOH + H_{2} {Na}_{2} O_{2} + 2 H_{2} O ⟶ 2 NaOH + H_{2} O_{2} Likewise Ba gives H_{2} while {BaO}_{2} gives H_{2} O_{2} Ba + 2 H_{2} O ⟶ Ba (OH)_{2} + H_{2} {BaO}_{2} + 2 H_{2} O ⟶ Ba (OH)_{2} + H_{2} O_{2}$