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Offline Centres

All straight wires are very long. Both AB and CD are arcs of the same circle, both subtending right angles at the centre O. Then the magnetic field at O is

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$\frac{μ_{0} i}{4 πR}$

$\frac{μ_{0} i}{4 πR} \sqrt{2}$

$\frac{μ_{0} i}{2 πR}$

$\frac{μ_{0} i}{2 πR} (π + 1)$

answer is C.

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Induction is only due to $AA'$ and $BB'$

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