All the three quadrilaterals ADEC, ABIH and BCGF are squares and ∠ABC=90∘ . If the area of ADEC=x2 and the area of AHIB =y2 units x2>y2 . then the area of BCGF is

Given (1) Area of square ADEC=x2(AC)2=x2AC=x(2) area of square AHIB=y2(AB)2=y2AB=yIn △ABC, ∠ABC=90∘AC2=AB2+BC2x2=y2+BC2x2−y2=BC2BC=x2−y2

All the three quadrilaterals ADEC, ABIH and BCGF are squares and ∠ABC=90∘ . If the area of ADEC=x2 and the area of AHIB =y2 units x2>y2 . then the area of BCGF is

Given (1) Area of square ADEC=x2(AC)2=x2AC=x(2) area of square AHIB=y2(AB)2=y2AB=yIn △ABC, ∠ABC=90∘AC2=AB2+BC2x2=y2+BC2x2−y2=BC2BC=x2−y2

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

All the three quadrilaterals ADEC, ABIH and BCGF are squares and $∠ ABC = 90^{\circ}$ . If the area of $ADEC = x^{2}$ and the area of $AHIB = y^{2} units (x^{2} > y^{2})$ . then the area of BCGF is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$(x^{2} - y^{2}) sq . units$

$(x^{2} + y^{2}) sq units$

$2 (x^{2} - y^{2}) sq . units$

None of these

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given (1) Area of square $ADEC = x^{2}$
$(AC)^{2} = x^{2}$
$AC = x$
(2) area of square $AHIB = y^{2}$
$\begin{array}{l} (AB)^{2} = y^{2} \\ AB = y \\ In △ ABC, ∠ ABC = 90^{\circ} \\ {AC}^{2} = {AB}^{2} + {BC}^{2} \\ x^{2} = y^{2} + {BC}^{2} \\ x^{2} - y^{2} = {BC}^{2} \\ BC = \sqrt{x^{2} - y^{2}} \end{array}$