Q.

alogb(logbx)logba=

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a

logxa

b

logbx

c

logax

d

logxb

answer is A.

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Detailed Solution

logb(logbx)logba=logb(logbx)×logab

=loga(logbx)

Now

alogb(logbx)logba=aloga(logbx)

=(logbx)

=logbx

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